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-4.905x^2+10x+27.5=0
a = -4.905; b = 10; c = +27.5;
Δ = b2-4ac
Δ = 102-4·(-4.905)·27.5
Δ = 639.55
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-\sqrt{639.55}}{2*-4.905}=\frac{-10-\sqrt{639.55}}{-9.81} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+\sqrt{639.55}}{2*-4.905}=\frac{-10+\sqrt{639.55}}{-9.81} $
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